Show how would you join 3 resistors of 9
WebJun 29, 2024 · Best answer (0 Two resistors in parallel and then one is series 1/R=1/R1+1/R2=1/9+1/9=2/9/2 R=9/2=4.5Ω R'=R+R3 =4.5+9=13.5Ω (ii) Two resistors in … WebDec 7, 2024 · (1) Two resistors in parallel and then one is series. 1/R=1/R 1 +1/R 2 =1/9+1/9=2/9/2. R=9/2=4.5 Ω. R'=R+R 3 (ii) Two resistors in series and one in Parallel . …
Show how would you join 3 resistors of 9
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WebAug 21, 2024 · Show how would you join three resistors, each of resistance \( 9 \Omega \), so that the equivalent resistance of the combination is(i) \( 13.5 \Omega \)(ii) ... Show how would you... WebShow how would you join three resistors, each of resistance is 9 ohm so that the equivalent resistance of the combination is 13.5 ohm and 6 ohm Report ; Posted by Richa Chauhan …
WebJan 31, 2024 · Join two resistors in parallel and one in series as shown in 1st figure. We know, in parallel , 1/R' = 1/R₁ + 1/R₂. Here , R₁ = R₂ = R₃ = 9Ω. Now, 1/R' = 1/9Ω + 1/9Ω ⇒ R' = … WebMar 30, 2024 · Transcript. Question 4 Page 216 How can three resistors of resistances 2 Ω, 3 Ω, and 6 Ω be connected to give a total resistance of (a) 4 Ω, (b) 1 Ω? Let R1 = 2 Ω R2 = 3 Ω R3 = 6 Ω The three resistors can be arranged in 8 ways All 3 parallel All 3 in series 2 parallel, 1 series - 3 cases 2 series, 1 parallel - 3 cases In series ...
WebDec 7, 2024 · Show how would you join three resistors, each of resistance 9 Ω so that the equivalent resistance of the combination is (1) 13.5 Ω (ii) 6 Ω? cbse class-10 Share It On Facebook Twitter Email 1 Answer +2 votes answered Dec 7, 2024 by Maryam (79.6k points) selected Dec 20, 2024 by Vikash Kumar Best answer WebApr 19, 2024 · Show how would you join three resistors, each of resistance `9 Omega` so that the equivalent resistance of the combination is (i) `13.5 Omega` , (ii) ...
WebMar 16, 2024 · 1). Let us take two resistors in parallel while other in series along them Therefore 1/ Rp = 1/ 9 + 1/9 = 2/9 Rp = 9/2 = 4.5 ohm Now, Rt = Rs + Rp = 9 + 4.5 = 13.5 ohm 2). Let us take two resistors in series and one in parallel along them Therefore Rs = 9+9 = 18 ohm 1/Rt = 1/ Rs + 1/ Rp = 1/ 18 + 1/ 9 = 1 + 2 / 18 = 3/18 Rt = 18/ 3 = 6 ohm
WebIt's a little shabby, but hopefully the color helps you identify or differentiate between them. And now that I know the voltage, again apply Ohm's law, this time to calculate the current. So that's the whole game over here. If you know voltage, you calculate the current. If you know the current, you calculate the voltage. qwatch ts-wrlc 設定WebMar 16, 2024 · 1) Join two resistors of 9 ohms in parallel with third resistor in series 1/Rp = 1/9 + 1/9 Rp = 4.5 ohms Now in series, Rs= 4.5 ohms + 9 ohms = 13.5 ohms 2) Now, … qwatch ts-wptcam2WebTo get an equivalent resistance of 9 Ω, atleast one six ohm resistor should be connected in series with the other resistors. Connecting the remaining two resistors in parallel will yield … shishman mediterranean grill austinshish mahal restaurant \u0026 pub pte. ltdWebThree resistors of 5 Ω, 10 Ω and 15 Ω are connected in series and the combination is connected to battery of 30 V. Ammeter and Voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the current flowing and potential difference across 10 Ω resistance? (2012) Answer: qwatch ts-wrlp マニュアルWebpossibility 1: Three 9Ω resistors are in parallel connection. INV ( (1/9) + (1/9) + (1/9)) = 3Ω possibility 2: Two 9Ω resistors are in parallel with one 9Ω in series connection. INV ( (1/9) + (1/9)) + 9 = 13.5Ω possibility 3: Two 9Ω resistors are in series with one 9Ω in parallel connection. INV ( (1/ (9+9)) + (1/9)) = 6Ω shishmaref airport codeWebMar 16, 2024 · Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω. Note:- If all 3 resistance were … shish mangal birstall